David Y.
—After I attempt to copy a list by setting new_list = old_list
, any modifications to new_list
also affect old_list
. What is the proper way to clone a list and avoid this?
The code new_list = old_list
does not create a second list, but merely causes new_list
to reference the same list object as old_list
. To make new_list
an independent copy of old_list
, we must explicitly copy the list. We can do this in two ways:
Performing a shallow copy is sufficient for lists containing simple, immutable types, such as numbers and strings. If a list contains other lists, dictionaries, or custom objects, a deep copy will be required.
We can use one of three methods to make a shallow copy:
list.copy
:
The list.copy
method makes a shallow copy of the original list:
old_list = [1, 2, 3, 4, 5] new_list = old_list.copy()
List slicing: We can also create a clone of a list using list slicing:
new_list = old_list[:]
This creates a new list by slicing the old list from its first to its final element. It is identical to list.copy
but may be less clear.
Using the list
constructor:
We can also create a new list from the existing list by passing it to the list
constructor.
new_list = list(old_list)
Again, this syntax produces identical results to the copy
method but may be less clear.
To make a deep copy of the list, we must use the deepcopy
function from Python’s built-in copy
module:
import copy old_list = [[1, 2], [3, 4]] new_list = copy.deepcopy(old_list) new_list[0][1] = 5 # change inner list in copy print(old_list) # will print [[1, 2], [3, 4]] print(new_list) # will print [[1, 5], [3, 4]]
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