David Y.
—My JavaScript code contains an array of objects that looks like this:
const objectList = [ { id: 10, name: "Jane" }, { id: 36, name: "Steven" }];
How can I find an object in this array based on the value of 'id'
? For example, I would like to write a function that returns “Steven” when given the input 36. How would I do this?
We can search an array for an object that satisfies an arbitrary condition using the Array
object’s find
method. We could therefore write the function described above as follows:
const objectList = [ { id: 10, name: "Jane" }, { id: 36, name: "Steven" } ]; function findNameById(list, id) { return list.find((obj) => obj.id === id).name; } console.log(findNameById(objectList, 36)); // will print "Steven"
The find
method iterates through the array, executing the function provided to it as an argument for each element. The first time it encounters an element for which the function returns a truthy value, it will stop iterating and return that element. In this code, we’ve used JavaScript’s arrow function expression syntax to keep things concise.
If we would like to get the array index of the object instead of the object itself, we can use findIndex
instead:
const objectList = [ { id: 10, name: "Jane" }, { id: 36, name: "Steven" } ]; function findNameById(list, id) { return list[list.findIndex((obj) => obj.id === id)].name; } console.log(findNameById(objectList, 36)); // will print "Steven"
If we need to get all elements that satisfy the condition rather than just the first one, we should use the filter
method, which returns an array of matched objects. To extract just the name
values from this array, we must use the map
method:
const objectList = [ { id: 10, name: "Jane", favoriteFood: "eggs" }, { id: 36, name: "Steven", favoriteFood: "bread" }, { id: 58, name: "Stephanie", favoriteFood: "bread" }]; function findNamesByFavoriteFood(list, favoriteFood) { return list.filter((obj) => obj.favoriteFood === favoriteFood).map((obj) => obj.name); } console.log(findNamesByFavoriteFood(objectList, "bread")); // will print ["Steven", "Stephanie"]
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