Asynchronous Callbacks in JavaScript

Naveera A.

—October 21, 2022

The ProblemThe Problem

How do callbacks work in JavaScript?

Let’s say we have the following code:

function first() {
  console.log('First');
}

function second() {
  console.log('Second');
}

function third() {
  console.log('Third');
}

We call the functions in order like so:

first();
second();
third();

And we get the following output:

First
Second
Third

Let’s add a setTimeout method in the second function, like so:

function first() {
  console.log('First');
}

function second() {
  setTimeout(() => {
    console.log('Second');
  }, 0);
}

function third() {
  console.log('Third');
}

Now if we call the functions in order as before, we get a different result:

First
Third
Second

Why does the second function run after the third function, even though the timer in the setTimeout function is set to 0?

The SolutionThe Solution

To understand why we are getting the unexpected output, we first need to understand the JavaScript event loop.

Since JavaScript is a single-threaded programming language, it can only process one statement at a time. To handle the asynchronous operations, like the setTimeout() method, JavaScript uses a concept called the event loop.

According to the documentation:

JavaScript has a runtime model based on an event loop, which is responsible for executing the code, collecting and processing events, and executing queued sub-tasks.

The event loop keeps track of the order of execution using a stack and a message queue.

You can think of the stack as the execution area, where each function is added in order. The queue is a waiting area for the asynchronous functions.

Let’s take a high-level look at how the event loop will execute our three functions.

Functions Without a Callback (or Asynchronous Code)Functions Without a Callback (or Asynchronous Code)

For the three functions without any asynchronous code, the browser will do the following:

• Add first() to the stack.

  • Run first() which will log First to the console.
  • Remove first() from the stack.

• Add second() to the stack.

  • Run second() which will log Second to the console.
  • Remove second() from the stack.

• Add third() to the stack.

  • Run third() which will log Third to the console.
  • Remove third() from the stack.

• Check the queue for messages (functions waiting to be processed).

  • Queue is empty.

• Execution cycle complete.

And we will get the following output, as expected:

First
Second
Third

Functions With a Callback (or Asynchronous Code)Functions With a Callback (or Asynchronous Code)

When we add the setTimeout() method to the second function, our execution steps look like the following:

• Add first() to the stack.

  • Run first() which will log First to the console.
  • Remove first() from the stack.

• Add second() to the stack.

  • Run second()
    • Add setTimeout() to the stack on top of second().
    • Run setTimeout API, which will start a timer. At the end of the timer, the anonymous function will be added to the message queue.
    • Remove setTimeout() from the stack.
  • Remove second() from the stack.

• Add third() to the stack.

  • Run third() which will log Third to the console.
  • Remove third() from the stack.

• Check the queue for messages.

  • Find the anonymous function from setTimeout()

• Add the anonymous function to the stack.

  • Run the anonymous function which will log Second to the console.
  • Remove the anonymous function from the stack.

• Check the queue again for messages.

  • Queue is empty.

• Execution cycle complete.

And we will get the following output:

First
Third
Second

The important thing to remember is that the timer in the setTimeout() method does not set the time after which the code will execute. It sets the time after which the event loop will add the anonymous function to the queue.

If we were working with an external web API, the anonymous function would be added to the queue after the API has returned its data.

The timer, or any other asynchronous code, cannot add the anonymous function directly to the stack at the end of its completion as it would interrupt the currently running function.

And the event loop will execute any function in the message queue only after executing all the top-level functions.

If we want to delay the execution of the third function until the second function has been completed, we can use the third function as a callback to the second function by passing it as an argument to the second function, like so:

function first() {
  console.log('First');
}

function second(cb) {
  setTimeout(() => {
    console.log('Second');

    // Execute the callback function
    cb();
  }, 0);
}

function third() {
  console.log('Third');
}

first();
second(third);

When we run the above code, we will get the desired output:

First
Second
Third