Clone a list in Python

David Y.
—The Problem
After I attempt to copy a list by setting new_list = old_list, any modifications to new_list also affect old_list. What is the proper way to clone a list and avoid this?
The Solution
The code new_list = old_list does not create a second list, but merely causes new_list to reference the same list object as old_list. To make new_list an independent copy of old_list, we must explicitly copy the list. We can do this in two ways:
- Shallow copy: Creates a new list, but does not create copies of the objects that the original list references. Both the original and the cloned list will still reference the same objects.
- Deep copy: Creates a new list and creates copies of every object in the original list references, recursively, ensuring that the two lists are entirely independent.
Performing a shallow copy is sufficient for lists containing simple, immutable types, such as numbers and strings. If a list contains other lists, dictionaries, or custom objects, a deep copy will be required.
We can use one of three methods to make a shallow copy:
list.copy: Thelist.copymethod makes a shallow copy of the original list:Click to Copyold_list = [1, 2, 3, 4, 5] new_list = old_list.copy()List slicing: We can also create a clone of a list using list slicing:
Click to Copynew_list = old_list[:]This creates a new list by slicing the old list from its first to its final element. It is identical to
list.copybut may be less clear.Using the
listconstructor: We can also create a new list from the existing list by passing it to thelistconstructor.Click to Copynew_list = list(old_list)Again, this syntax produces identical results to the
copymethod but may be less clear.
To make a deep copy of the list, we must use the deepcopy function from Python’s built-in copy module:
import copy old_list = [[1, 2], [3, 4]] new_list = copy.deepcopy(old_list) new_list[0][1] = 5 # change inner list in copy print(old_list) # will print [[1, 2], [3, 4]] print(new_list) # will print [[1, 5], [3, 4]]
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