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Generate a random integer in C#

Generate a random integer in C#

David Y.

The ProblemJump To Solution

How do I generate a random integer in C#?

The Solution

We can generate pseudorandom numbers using C#‘s System.Random class. For example:

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Random rng = new Random(); int rand1 = rng.Next(100); // number between 0 and 99

We can also specify a lower bound for generated numbers:

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int rand2 = rng.Next(10, 20); // number between 10 and 19

Note that the randomness generated by calling rng.Next is only pseudorandom, not truly random. This is sufficient for applications where true randomness is not critical, such as games or visualizations, but should not be used for anything related to security.

To generate truly random numbers, we should use the RandomNumberGenerator class from System.Security.Cryptography. For example:

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var randomBytes = new byte[4]; using (var rng = RandomNumberGenerator.Create()) { rng.GetBytes(randomBytes); uint trueRandom = BitConverter.ToUInt32(randomBytes, 0); }
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