Map Entries are Unaddressable

Evan Hicks

The Problem

The error: ./prog.go:15:10: cannot call pointer method on m[“bar”]
./prog.go:15:10: cannot take the address of m[“bar”]

package main

import (
    "fmt"
)

type Bar struct {}

func (b *Bar) Fizz() {
    fmt.Println("buzz")
}

func main() {
    m := map[string]Bar{"bar": Bar{}}
    m["bar"].Fizz()
}
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The Solution

There are actually two different bugs here, hence the two different compile errors. The first bug is that the function Fizz is defined on a pointer receiver *Bar and m is a map of non-pointer Bar. Normally this isn’t an issue, because Go will automatically create a pointer to the object and then call Fizz on that. However, since map entries are not addressable, Go cannot create a pointer and this error occurs.

The fix: There are two ways to fix this. The first is to change m to type map[string]*Bar and then have &Bar{} as the value. The other solution shown below is to change the Fizz method to not be a pointer receiver.

package main

import (
    "fmt"
)

type Bar struct {}

func (b Bar) Fizz() {
    fmt.Println("buzz")
}

func main() {
    m := map[string]Bar{"bar": Bar{}}
    m["bar"].Fizz()
}
Click to Copy

Further Reading

If you’re looking to get a deeper understanding of how Go application monitoring works, take a look at the following articles:

• Sentry’s unified Go SDK
• How slow is slow?
• Getting started with the Go SDK (docs)