How can I get the named parameters from a URL using Flask?
Naveera A.
—The Problem
How can I get the named parameters from a URL using Flask?
The Solution
Flask provides a global request object that contains all sorts of information about the current HTTP request. Flask also parses the incoming request data for you.
You can use the args property of this global request object to get the values of query parameters.
For example, to access the query parameters of the following URL:
http://mysite.com/query_example?language=Python&framework=Flask
You can use the get method on request.args, like so:
# import main Flask class and request object from flask import Flask, request # create the Flask app app = Flask(__name__) @app.route('/query_example') def query_example(): language = request.args.get('language') framework = request.args.get('framework') print(f'language: {language}, framework: {framework}') return 'Query Parameters Example' if __name__ == '__main__': app.run(debug=True, port=5000)
You will get:
language: Python, framework: Flask
The request.args attribute is an ImmutableMultiDict that implements all standard dictionary methods.
The get method also takes optional arguments for default value and type. The following example should explain this behavior:
def query_example(): language = request.args.get('language', default='Python') framework = request.args.get('framework', default='Flask')
For /query_example?language=JavaScript:
language: JavaScript, framework: Flask
For /query_example:
language: Python, framework: Flask
For /query_example?language=JavaScript&framework=Express:
language: JavaScript, framework: Express
For /query_example?framework=Express:
language: Python, framework: Express
Further Reading
- SentryFlask Error Monitoring
- Syntax.fmListen to the Syntax Podcast
- Community SeriesIdentify, Trace, and Fix Endpoint Regression Issues
- Listen to the Syntax Podcast
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