Avoiding `NullPointerException` in Java

Lewis D.

—July 12, 2022

The ProblemJump To Solution

In Java, a NullPointerException occurs when a variable that is being accessed has not yet been assigned to an object, in other words, the variable is assigned as null.

If you have read the Sentry answer to Is Java Pass-By-Reference or Pass-By-Value?, you might know that in Java, variables are simply pointers to objects in memory. Therefore, a null pointer exception will occur when the code is pointing to something in memory that does not exist.

The Java API documentation on NullPointerException lists a couple of scenarios where this exception could be invoked:

• Calling the instance method of a null object.
• Accessing or modifying the field of a null object.
• Taking the length of null as if it were an array.
• Accessing or modifying the slots of null as if it were an array.
• Throwing null as if it were a Throwable value.

The Solution

Let’s take a look at a concrete example of where a NullPointerException might be thrown.

Consider the following code example:

class NullPointerExample {
    private static void printFirstElement(String[] array) {
        System.out.println(array[0]);
    }

    public static void main(String[] args) {
        String[] myStringArray = null;
        printFirstElement(myStringArray);
    }
}

Executing this code will result in the following stack trace:

Exception in thread "main" java.lang.NullPointerException
    at NullPointerExample.printFirstElement(NullPointerExample.java:6)
    at NullPointerExample.main(NullPointerExample.java:11)

This happens because in our printFirstElement() method, we attempted to access the first element of an array which does not exist. Similarly, taking the length of this given array would yield the same result. We could make this code null-safe by adding a check for null before attempting to access the first element:

class NullPointerExample {
    private static void printFirstElement(String[] array) {
        if (null != array){
            System.out.println(array[0]);
        }
        else{
             System.out.println("The array was null!");
        }
    }

    public static void main(String[] args) {
        String[] myStringArray = null;
        printFirstElement(myStringArray);
    }
}

Executing this code now will yield the following output:

The array was null!

This is one important technique we can use to avoid tumbling into a NullPointerException during code execution. Some tips for avoiding a NullPointerException include:

• Perform null checks to ensure that objects are correctly initialized before accessing any of the object’s methods.
• Use primitives (where it makes sense) such as int, boolean and char, as these cannot be assigned as null and therefore cannot cause a NullPointerException.
• When first initializing objects, attempt to assign default or temporary values to them.
• Use a tool like FindBugs, which performs static analysis of code and can detect NullPointerException issues before you actually execute any of your code.
• Use a tool like NullAway which acts on @NotNull and @Nullable annotations.

Further Reading

Is Java Pass-By-Reference or Pass-By-Value?